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how do i factor 4x^2+9xy-9y^2
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i found that the factored version of 4x^2+9xy-9y^2 is (x+3y)(4x-3y)
thanks how did you find the answer?
Suppose you have the problem: x2 +6x+9 you try to find two numbers that add to be 6 and multiply to be 9. in this case it's 3 and 3. so you exchange the 6x for 3x +3x . . . x2 +3x +3x +9 then you group the first two and the second two terms . . . (x2+3x)+ (3x+9) next you take out the biggest number they have in common.and leave whats left in the ( ) x(x+3)+ 3(x+3) now the answer is the stuff inside the ( ) times the stuff outside (x+3)(x+3) (by the way, sorry or the delay, i had to brb) hope this helps
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