Question

Solve the equation on the interval [0, 2π).
sin^2x - cos^2x = 0
A. π/4
B. π/4 ; π/6
C. π/4 ; π/3
D. π/4 ; 3π/4 ; 5π/4 ; 7π/4

Answer 1

D should work since \(\sin^2(x)=\cos^2(x)\) means \(\sin(x)=\pm\cos(x)\)

Answer 2

Thank you!

Answer 3

at all those numbers you get \(\pm\frac{\sqrt{2}}{2}\) for sine and cosine

Answer 4

yw