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OpenStudy (baldymcgee6):
For what values of a and b is the following parametric function continuous?
http://screencast.com/t/ydAe0nVzELd
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OpenStudy (baldymcgee6):
@hartnn
OpenStudy (baldymcgee6):
I have the solution, but i don't get it... Do you want me to post the solution?
hartnn (hartnn):
which part u didn't get ?
for limit to be continuous, u need to have lim x->0- ... = lim x->0+ ..
OpenStudy (baldymcgee6):
why at 0?
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hartnn (hartnn):
because the point of dis-continuity can be 0 only... as the function behaves differently (different definition) before and after 0
OpenStudy (baldymcgee6):
because of the domain restrictions?
hartnn (hartnn):
u can say that, but mostly its because of t<=0 ..... t> 0
if it were
t<=2..... t>2, then u would have checked at x=2
hartnn (hartnn):
*t=2
OpenStudy (baldymcgee6):
okay... how does a=b?
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hartnn (hartnn):
because , for continuity , lim x->0- needs to be equal to x->0+
and lim x->0- was 1
so, x-> 0+ = a/b = 1
OpenStudy (baldymcgee6):
ohhhhh..
OpenStudy (baldymcgee6):
thank you again!
hartnn (hartnn):
welcome ^_^
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