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Mathematics 19 Online
OpenStudy (baldymcgee6):

For what values of a and b is the following parametric function continuous? http://screencast.com/t/ydAe0nVzELd

OpenStudy (baldymcgee6):

@hartnn

OpenStudy (baldymcgee6):

I have the solution, but i don't get it... Do you want me to post the solution?

OpenStudy (baldymcgee6):

http://screencast.com/t/C8XAD3vk1O

hartnn (hartnn):

which part u didn't get ? for limit to be continuous, u need to have lim x->0- ... = lim x->0+ ..

OpenStudy (baldymcgee6):

why at 0?

hartnn (hartnn):

because the point of dis-continuity can be 0 only... as the function behaves differently (different definition) before and after 0

OpenStudy (baldymcgee6):

because of the domain restrictions?

hartnn (hartnn):

u can say that, but mostly its because of t<=0 ..... t> 0 if it were t<=2..... t>2, then u would have checked at x=2

hartnn (hartnn):

*t=2

OpenStudy (baldymcgee6):

okay... how does a=b?

hartnn (hartnn):

because , for continuity , lim x->0- needs to be equal to x->0+ and lim x->0- was 1 so, x-> 0+ = a/b = 1

OpenStudy (baldymcgee6):

ohhhhh..

OpenStudy (baldymcgee6):

thank you again!

hartnn (hartnn):

welcome ^_^

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