Question

Which is a solution of the compound inequality 3k + 4 < 2 or 2k − 3 > 2?
Answer

k > 2/3 or k < -5/2

k < -2/3 or k > 5/2

k < 2 or k > 5/2

k > 2 or k < -1/2

Answer 1

I got B.

Answer 2

solve them both

\[3k + 4 < 2 \]subtract 4 from both sides:\[3k<-2\]divide both sides by 3:\[k<-{2\over3}\]
\[2k − 3 > 2\]add 3 to both sides:\[2k>5\]divide both sides by 2:\[k>{5\over2}\]

so the solution is \(\large k < -{2\over3} ~~or~~ k > {5\over2}\)
Option \(\text{B}\)

Answer 3

Good Job @ramirokool ! :D

Answer 4

(: