Question

help me plzz

Consider the line that passes through the point (-1, 6) and has a slope of -4.

Part 1: Write the equation of this line using point-slope form. (2 points)
Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. (2 points)
Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work. (2 points)

Answer 1

@AccessDenied @arman1002 help plzz

Answer 2

use the equation
\[ \large y-y_0=m(x-x_0) \]

Answer 3

u have the slope m=-4 and the point (-1,6)

Answer 4

Part 1
1) use point -slope form y-y1=m(x-x1) so the equation would look like y-6=-4(x+1)

Part Two
2) then the equation becomes y-6=-4x-4
3) add six to both sides to get y=-4x+2

Part 3
4) use the slope and y-intercept of the above equation
5) the standard from would look like y-2=x+0

Answer 5

if correct please click best response.

Answer 6

Standard form is \(ax + by = c\). To get this form from \(y = \neg 4x + 2\), we simply add \(4x\) to each side.

\(4x + y = 2\)