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OpenStudy (anonymous):

Q

OpenStudy (anonymous):

OpenStudy (anonymous):

First question, why is \(U_i=mgh_f\) instead of \(U_i = mgh_i\)?

OpenStudy (experimentx):

that is the total energy of the system!! the energy of the system is constant if there were no other forces acting. i.e. Kinetic Energy + Potential Energy = constant = total energy now given that the pendulum starts from rest at height h_i, K.E. = 0, total energy = P.E

OpenStudy (anonymous):

But with the initial height hi, isn't the PE = \(mgh_i\)? Why is it \(mgh_f\)?

OpenStudy (anonymous):

|dw:1353427300243:dw|

OpenStudy (anonymous):

Initial PE = mg(l-lcosθi) = mgl (1-cosθi) Final PE = mg(l-lcosθf)= mgl(1-cosθf) PE loss = change in PE = mgl[(1-cosθf) - (1-cosθi)] = mgl(cosθi - cosθf) ??

OpenStudy (experimentx):

|dw:1353430286611:dw|

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