Question

P.E of a particle free to move to along x-axis is given by (x^3 - x^2/2)J where x is in metre . The particle is initially kept at x=0 and then given a sight displacement x in +ve direction. The force acting on the particle will displace it to a Distance ?

Answer 1

@experimentX @JFraser @siddhantsharan @gerryliyana

Answer 2

@ghazi

Answer 3

F = - d(PE)/dx

Answer 4

- (3x^2 - x)

Answer 5

F = 0 ... find the equilibrium

Answer 6

x = 1/3

Answer 7

Thxx.)