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OpenStudy (anonymous):
find d^2y/dx^2 in terms of x and y x^2-y^2=16
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OpenStudy (anonymous):
wait, which one do u need help with?
OpenStudy (anonymous):
in terms of dy/dx, the answer is -16/y^3, I don't how to get there
OpenStudy (anonymous):
this is an implicit problem x^2-y^2=16 2x-2y(dy/dx)=0 I don't know what to do next
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