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Mathematics 8 Online
OpenStudy (anonymous):

find d^2y/dx^2 in terms of x and y x^2-y^2=16

OpenStudy (anonymous):

wait, which one do u need help with?

OpenStudy (anonymous):

in terms of dy/dx, the answer is -16/y^3, I don't how to get there

OpenStudy (anonymous):

this is an implicit problem x^2-y^2=16 2x-2y(dy/dx)=0 I don't know what to do next

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