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Mathematics 11 Online
OpenStudy (anonymous):

What is the equation of the graph? http://prntscr.com/k9bzc

OpenStudy (anonymous):

Ok.. well first of can you tell me the co ordinates of the centre? from the graph?

OpenStudy (anonymous):

Nope, could you walk me through solving the problem. I should have stated I needed guidance.

OpenStudy (anonymous):

yes.. if there is any point on a graph.. do you know how to get its co ordinates?

OpenStudy (anonymous):

New to this stuff, so I guess not.

OpenStudy (anonymous):

ermm. my laptop is about to switch off.. you better google. basic co ordinate geometry!

OpenStudy (anonymous):

The x coordinate is the value along the horizontal (left-right) line where the center of the circle is located. From your picture, the x value is -1. Can you understand why? Do you agree with this? The y coordinate is the value along the vertical (up-down) line where the center of the circle is located. From your picture, the y value is +4. Do you agree with that part? If so, we can agree the x,y coordinates of the center of the circle are (-1,4)

OpenStudy (anonymous):

If we're good so far, the next step is: the standard equation of a circle is \[(x-h)^{2}+{(y-k)}^{2}=r^{2}\] So next just substitute the h and k with the x and y coordinates of the center of your circle, so: \[(x-(-1))^{2}+{(y-4)}^{2}=r^{2}\] or \[(x+1))^{2}+{(y-4)}^{2}=r^{2}\] Now all you need is the length of your radius, square it and that's the value you substitute for: \[r^{2}\] Questions?

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