Let f(x)= 3x – 6 and g(x) = x –2. Find f/g and its domain.
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OpenStudy (anonymous):
Factor, f(x). Cancel common factor with g(x). Set g(x)=0 to find restriction on domain.
OpenStudy (dinmosiaren):
would you do that by multiplying by the reciprocal of g(x)
OpenStudy (dinmosiaren):
what did you get?
for the factor
OpenStudy (anonymous):
Multiplying by the reciprocal means the same thing. Division is defined in that way.
I think you should see the factor well enough yourself. Try working it out and let me know what you see.
OpenStudy (dinmosiaren):
okay i will
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OpenStudy (dinmosiaren):
i got 3x^2-12 divided by x^2 -4
Now what?
OpenStudy (hba):
Would you mind taking common ?
OpenStudy (dinmosiaren):
what i got 0
OpenStudy (dinmosiaren):
i divided and i got 3-3 which would be 0
is that right?
OpenStudy (hba):
Let me do it for you.
3(x^2-4)/x^2-4
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OpenStudy (dinmosiaren):
oh okay
duh
OpenStudy (hba):
What do you get ?
OpenStudy (dinmosiaren):
now what
you get 3
OpenStudy (hba):
Exactly .....
OpenStudy (dinmosiaren):
okay so 3 is f/g what about the domain?
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OpenStudy (dinmosiaren):
all real numbers?
OpenStudy (dinmosiaren):
or is it all real numbers except for 2
OpenStudy (hba):
Set denominator = 0 and solve for x
OpenStudy (hba):
You will know the restriction of the domain.
OpenStudy (dinmosiaren):
so it would be 3x-6/0?
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OpenStudy (hba):
No no set 0=x-2 >x=2 is a restriction
OpenStudy (hba):
on the domain.
OpenStudy (dinmosiaren):
so the answer is 3 in f/g
and the domain is all real numbers except for 2
OpenStudy (dinmosiaren):
right
OpenStudy (hba):
Awesome :)
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OpenStudy (dinmosiaren):
thanks for the help...im good at math I just struggle with some questions