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Find the absolute value of -3 – 6i.
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l-3-6il i am not sure plz don't mark this answer in your test or whatever u are doing i am not sure.
uhh ok
\[a+bi\] has absolute value \(a^2+b^2\)
oops i mean \[\sqrt{a^2+b^2}\]
ok
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would i put the negative on the 3?
in your case it would be \[\sqrt{3^2+6^2}\]
nope all is positive don't think about minus signs or the \(i\) just use \(\sqrt{a^2+b^2}\)
ok thx
so i'll get sqrt of 45?
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Yeah, sqrt45=sqrt9*sqrt5=3*sqrt5
i got it, thx anyways
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