use the method of substitution to solve the system of linear equations 5x+3y=5/6 y=6x-1 find the ordered pairs
Just replace y in the first equation with the expression of the second equation
ok so it would be 5x+3(6x-1)=5/6
Yup
ok ty
are you stuck on this? from the chat above it looks like you know what to do now.
yea im stuck
what are you having difficulty with?
trying to find the ordered pairs
well you got this part correct: 5x+3(6x-1)=5/6 so solve this to find a value for x. Then use: y=6x-1 to get a value for y. Then your solution will be the ordered pair given by (x, y) where you replace x and y by the numbers you found above.
well i have come up with 5x+18x=1=5/16 then 23x-1=5/16 and then i get stuck
so you do not know how to solve for x - looks like you first need to learn some algebra. I would recommend that you view these short videos: http://www.khanacademy.org/math/algebra/introduction-to-algebra that will give you a good grounding on alegra which will make it easier for you to solve questions like this one.
you have to get x on one side by it self
yes
so yo have to add like terms to do that right
yes, but your initial expansion of: 5x+3(6x-1)=5/6 was incorrect
what is: 3(6x-1)
when expanded?
so i come up with 23x -1=5/6 divide both the 23 and the one by 23 to come up with x-1/23=5/6 then subtract both sides by 1/23
so you come up with x = 5/6-1/23
please look above ^^^ you got the initial expansion wrong
what is: 3(6x-1) when expanded?
oh its 18x -3
correct, you start again from: 5x+3(6x-1)=5/6
also - to simplify your life - I would first get rid of the fractional parts in this equation. you can do that by multiplying both sides by 6.
5x +18x-3=5/6
correct - now multiply both sides by 6 to get rid of the fraction
so it would be (23x)6-3=5/6(6)
when you multiply both sides - you must ensure that EVERY term is multiplied
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