Question

write an equation for the line parallel to the given line C. C(3,6) y=-2x+3

Answer 1

the line paralle to the above line is of the form y=-2x +k (just for parallel lines constant term is different as their slopes are same )
since our line passes throug(3,6)
we have 6=-2(3) +k
or k=12
hence the reqd line is y=-2x +12

Answer 2

what would that look like in slope intercept form?

Answer 3

And how did you find k?

Answer 4

y = mx+b

y = -2x+b

6 = -2(3) + b

6 = -6 + b

6+6 = b

12 = b

b = 12


So the parallel equation is y = -2x + 12

Answer 5

thanks!