Question

Simplify. Show work and explain how you did it.

3. square root of 3 + sq root of 72 - sq root of 128 + sq root of 108

Answer 1

\[\sqrt{3} + \sqrt{72} - \sqrt{128} + \sqrt{108}\]

Answer 2

@jiji501 Are you trying to figure it out???

Answer 3

umm,
wat are the common factors of 72 128 and 108?

Answer 4

72: 1,2,3,4,6,8,9,12,18,24,36,72
128: 1, 2, 4, 8, 16, 32, 64 and 128
108: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108

Answer 5

now identify the square numbers that are factors...

e.g. \[\sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \times \sqrt{2} = 6\sqrt{2}\]

use the same process for the other numbers...

Answer 6

pick the biggest square root

Answer 7

sq root of 3 is the same correct

Answer 8

thats correct... and you should have 2 square rt 3 terms and 2 sq rt 2 terms...

just add or subtract then... just the same as like terms in algebra.

Answer 9

what do I do once I get done with all that

Answer 10

thats it,,, what answer did you get..?

Answer 11

does the square root of 3 have a 1 in front of it

Answer 12

nope...its like x its really 1x but we just write x

Answer 13

but could it

Answer 14

it could...

Answer 15

is the answer 7 square root of 3 - 2 square root of 2

Answer 16

thats it... well done...

Answer 17

I meant to type it in