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find the equations for the tangent line and normal line to x^2+y^2=9 at (2, rad5)
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What's rad5 supposed to mean
\[x ^{2}+y ^{2}=9 at (2, \sqrt{5)}\]
Find the derivative of the function first
i did that but what does it mean by normal line
Perpendicular to the tangent line
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\[y=-x \div \sqrt{9-x ^{2}}\]
So find the derivative at the point (2,sqrt(5))
okay i found the tangent line but how do you find the normal line?
If you have the slope of a line, how do you find the slope that's perpendicular to it?
negative reciprocal
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i think i got it! thank you
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