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Linear Algebra
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what is slope -2/3,yintercept(0,5)
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\[y-5=-2/3(x-0)\]
\[y=-2/3x+5\]
is that what you were looking for? the equation of the line?
i can show you how to do that
you use the "point slope" formula which is y – y1 = m(x – x1)
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first find the gradient between those line... \[m = \frac{ x _{2}-x_{1} }{ y _{2}-y_{1} }\] then by substituting one of the point to the general linear equation : \[y-y _{1} = m(x-x _{1})\] your answer should be... \[y=x+5\] *try it yourself...
thankyou
y1 is the your y value @ the point (0, 5) and x1 is the x value at the point (0 ,5) M is the slope plug in the numbers and simplify
thankyou
you're welcome
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so is m always going to be the slope
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