Question

What is the solution of the linear-quadratic system of equations?

y= x^2 + 5x - 3
y-x =2

Answer 1

I am totally not getting this...help!

Answer 2

Solve one of the equations for either y or x and then plug that into the other equation for the respective variable

Answer 3

So to get y by itself, would I change the bottom equation to y = x +2?

Answer 4

y-x=2
y=x+2
x^2+5x-3=x+2

Answer 5

now try to factorise

Answer 6

y = x - 3?

Answer 7

?

Answer 8

sorry Im not good at factorising.

Answer 9

X^2+5x-3=x+2
X^2+5x-x-3-2=0
got it?

Answer 10

x^2+4x-5=0

Answer 11

now see, 5+-1=4
-1*5=-5

Answer 12

so x^2+4x-5=(x+5)(x-1)=0

Answer 13

now can u find values of x?

Answer 14

so now I substitute to find x? Im sorry, I have never been good at this.

Answer 15

(x+5)(x-1)=0.
understood this?

Answer 16

yes

Answer 17

and if x-1 = 0 then x =1

Answer 18

of course. now we have 2 values of x. can you find y with that?

Answer 19

Yeah I think so. I'll go try it

Answer 20

x=-5 or x=1

Answer 21

that's nice, u r a gud student, i feel. bye

Answer 22

thanks. So x = 7 or 3?

Answer 23

I mean Y = 7 or 3?

Answer 24

for x=-5,
y--5=2
y+5=2
y=2-5
other value is right.

Answer 25

- x*- x= +x^2

Answer 26

x--x=x+x.
got it?