how do i graph a parabola, given the points? (-2,4) (-4,0) (0,0)
it clear that there is two x -int at y=o and a y-int at x=o ur turning point will be (-2;4) try to graph it and let see
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im asked to choose the correct equation that represents this parabola
From the symmetry, like hubert pointed out, you can see that (-2,4) is the vertex. The vertex form of a parabola is \(\large y=a(x-h)^2+k\) where (h,k) is the vertex. You can use that and one of the other points to solve for a.
There is a more general way to do it that requires solving a system of linear equations, but since you have the vertex, it's a single equation short cut.
im new at this....what is a vertex
A vertex is like a corner or turning point. In the case of your parabola it is the maximum point in the range between where it's increasing and where it's decreasing.
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