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I have a question on the last part. That I don't understand.
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find H(0).. that will be your y-intercept.
I am not sure what you mean?
He means x= 0 find value of y
okay so does that mean I have to set up x^2-36, x^4-81 to 0
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when ever a curve crosses the y-axes, its x value is always zero. so, to find the y-intercept, you just need to evaluate the function at x=0
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