Consider the line y=-(6/5)x-2 Find the equation of the line that is parallel to this line and passes through the point (-5,-6) Find the equation of the line that is perpendicular to this line and passes through the point (-5,-6)
plug in the coordinates to the slope intercept form. remember that when it's parallel, the slope stays the same and when it's perpendicular the slope becomes opposite reciprocal.
will the perpindicular slope be negative?
it shouldn't be. because you multiply the negative sign to 6/5 so that will be -6/5. and the perpendicular slope is going to be 5/6
when do I multiply the negative sign?
y=-(6/5)x-2 so you see that negative before the parenthesis? that should be understood as -6/5
oh ok thank you. so would the parallel equation be y=-6/5
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