Question

How do you solve this trig equation?

sin=csc

Answer 1

The answer should be values on the unit circle.

Answer 2

You can't solve it. They are not equivalent

Answer 3

\[\sin(x)=\frac{1}{\sin(x)}\iff \sin^2(x)=1\iff \sin(x)=\pm1\]

Answer 4

Well, according to my book the answer is \[\pi/2 & 3\pi/2\]

Answer 5

so look to see for what value of \(x\) you have \(\sin(x)=1\) and for what value of \(x\) you have \(\sin(x)=-1\)

Answer 6

and yes, the book is right, those are the two values of \(x\) between \(0\) and \(2\pi\) that work