Question

Solve each question by completing the square.
2x^2+3x=8

Answer 1

factor it using the quadratic formula.

Answer 2

\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
\[x=\frac{ -3 \pm \sqrt{3^2-4*2*8}}{ 2*2 }\]
\[x=\frac{ -3\pm \sqrt{9-64} }{ 4 }\]
\[x=\frac{ -3 \pm i \sqrt{55} }{ 4 }\]

Do you mean this? If not, show me.

Answer 3

\[\frac{ -3 \pm 13 }{ 4 }\]

Answer 4

Your equation above was wrong, your c was suppose to be a negative.

Answer 5

How do you get your 13? I keep getting \[x= \frac{ -3 \pm \sqrt {73} }{ 4 }\].