Question

Please Help! what are the zeros of the function? what are their multiplicities? f(x)=x^4-4x^3+3x^2

Answer 1

hint:


f(x)=x^4-4x^3+3x^2


0 = x^4-4x^3+3x^2


x^4-4x^3+3x^2 = 0


x^2(x^2-4x+3) = 0


x^2(x-3)(x-1) = 0

Answer 2

I am still really confused I dont get what the question is asking me!

Answer 3

it's asking you to solve 0 = x^4-4x^3+3x^2 for x

Answer 4

which is equivalent to x^2(x-3)(x-1) = 0

Answer 5

it wants to know if its A. The numbers -1 and -3 are zeroes of multiplicities2;the numbers 1 and 3 are zeroes of multiplicities 1.
B. the number 0 is a zero of multiplicity2;the numbers 1 and 3 are zeroes of multiplicty 1.
C. The numbers 0 and 1 are the zeroes of multpilcty2; the number 3 is a zero of multiplcty1.
D.The number 0 is zero of multiplicty2;the numbers -1 and -3 are zeroes of multiplicty

Answer 6

x^2(x-3)(x-1) = 0

x^2 = 0, x-3=0, or x-1=0

Answer 7

solve each for x

Answer 8

x=-x^2 x=3 x=1

Answer 9

so how do i know which one it is?

Answer 10

x^2 = 0 ---> x = 0 (multiplicity of 2)

Answer 11

yep

Answer 12

thanks so much!! I really apperciate it!

Answer 13

np