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OpenStudy (anonymous):
Find tan θ if sec θ = (sqrt26)/5 and sin θ < 0.
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OpenStudy (anonymous):
\[\tan\theta = \frac{\sin\theta}{\cos\theta}\]
\[\sec\theta = \frac{1}{\cos\theta}\]
OpenStudy (anonymous):
I got cosθ= (5sqrt26)/26
OpenStudy (anonymous):
also you can form a triangle from the secant ratio since:
\[\sec\theta = \frac{hyp}{adj}\]
|dw:1354140830832:dw|
OpenStudy (anonymous):
since the tan requires the opposite side:
\[\tan\theta = \frac{opp}{adj}\]
you should solve missing side with pythagorean
OpenStudy (anonymous):
So tanθ= 1/5 ?
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OpenStudy (anonymous):
right.
OpenStudy (anonymous):
do the other questions your working on ask you to find an angle? if so i think that's why they give you: sin θ < 0
OpenStudy (anonymous):
but in this context it appears to be extra information.
OpenStudy (anonymous):
Well 1/5 isn't an option as an answer, but - 1/5 is...
OpenStudy (anonymous):
@Mathmuse
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jimthompson5910 (jim_thompson5910):
since sin(theta) < 0, cos(theta) > 0 and tan = sin/cos, this means that tan(theta) is negative
OpenStudy (anonymous):
Thank you @jim_thompson5910 !
jimthompson5910 (jim_thompson5910):
np
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