Question

Algebraically find all the critical numbers of the function f(x)=xe^(-3x)

Answer 1

Were you able to find f'(x) alright? :)

Answer 2

e^(-3x)(1-3x)

Answer 3

Simplified? ok cool :)

Sooooo, to find critical points, we set the first derivative equal to 0 yes?
Having trouble understanding what's happening with the exponential or what? :D

Answer 4

I had no idea it was that simple... just find the derivative and set it equal to zero?

Answer 5

After you set it equal to 0, you'll need to solve for x :)

Answer 6

well, yeah of course lol (: thank you!

Answer 7

oh heh ^^ np