Question

How do I graph these (Algebra II) please?
1) y = x^2 + 4x + 1

2) f(x) = 3x^2 - 4x - 2

Answer 1

You can plot a series of points and draw a curve through them

or you can plot the vertex and and a point on the parabola

Answer 2

but how do i do that?

Answer 3

to get any point, you plug in any number for x to get a corresponding y value

when x = 0, y is...


y = x^2 + 4x + 1


y = (0)^2 + 4(0) + 1 ... plug in x = 0


y = 0 + 4(0) + 1


y = 0 + 0 + 1


y = 1


So when x = 0, y is y = 1 giving us the point (0, 1)

Answer 4

I can do that for both of them?

Answer 5

When x = 1, y is...


y = x^2 + 4x + 1


y = (1)^2 + 4(1) + 1 ... plug in x = 1


y = 1 + 4(1) + 1


y = 1 + 4 + 1


y = 6


So when x = 1, y is y = 6 giving us the point (1, 6)

Answer 6

yes

Answer 7

you can do this for any value of x to get any point

once you have enough points, plot them and draw a curve through them

Answer 8

do each equation one at a time though

Answer 9

thank you so much :)

Answer 10

np