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someone help? how much interest is earned by investing 20000 at 8.5%p.a continuously compounded.At what year would you reach 1million ?
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\[P=20000e^{1.085t}\]
\[1000000=20000e^{1.085t}\]
\[5=e^{1.085t}\] \[ln(5)=ln(e^{1.085t})=1.085t*ln(e)=1.085t\] \[t=ln(5)/1.085=1.48335\]
so 1.48335 is going to be the final answer?
yes. after 1.48335 years you will have $1000000. but it asks in which. year. since 1.48335 is more than one the answer is in the second year.
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oh ok then thankyou
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