Question

why is
-((m(x-a)+c))
equal to
-m(x-a)-c

where does the -c come from??

Answer 1

just multiply in the negative -[ (m(x-a) + c ]
[ -(m(x-a) -c ]

Answer 2

why isnt the (x-a) affected?

Answer 3

Well if we just look at -m(x-a) if we multiply through we get (-mx + ma)

Answer 4

ohh u have to distribute the m too if u want to distribute the negative tyy

Answer 5

no problem