The position s of a point (in feet) is given as a function of time t (in seconds).

s = ( square root t) + 4t^2 ; t=25

(a) Find the point's acceleration as a function of t.

s''(t) = ???

Question

The position s of a point (in feet) is given as a function of time t (in seconds).

s = ( square root t) + 4t^2 ; t=25

(a) Find the point's acceleration as a function of t.

s''(t) = ???

anonymous · Answer

so basically i'm pretty sure you just solve for t, which (by plugging into your calculator) gives you 2505ft

anonymous · Answer

yea but i think they want me to find the derivative of that, thats when s'(t) means

anonymous · Answer

oh well then sorry, I don't even know what a derivative is (I'm only in Precalc)