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Mathematics 16 Online
OpenStudy (anonymous):

The position s of a point (in feet) is given as a function of time t (in seconds). s = ( square root t) + 4t^2 ; t=25 (a) Find the point's acceleration as a function of t. s''(t) = ???

OpenStudy (anonymous):

so basically i'm pretty sure you just solve for t, which (by plugging into your calculator) gives you 2505ft

OpenStudy (anonymous):

yea but i think they want me to find the derivative of that, thats when s'(t) means

OpenStudy (anonymous):

oh well then sorry, I don't even know what a derivative is (I'm only in Precalc)

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