Question

secB/sinB - sinB/cosC = cotB
if someone could solve i would really appreciate it please :)

Answer 1

Rewrite the sec and cot as their equivalent sin and cosine formula

Answer 2

use sine and cosine

Answer 3

sec= 1/cos
cot=1/tan
tan=sin/cos

Use that information to simplify it further

Answer 4

(1/cosB)/(sinB) - sinB/cosB = cotB

Answer 5

cotB=1/tanB ??

Answer 6

I thought the original problem had sin B/cos C, which you can't combine together in any way

Answer 7

its cosB

Answer 8

So yes it's true. You are correct