Question

help please ??find any intercepts y=2x- √x²+1
thanks (: !

Answer 1

graph it, thats the easiest

Answer 2

other than that you could do:
set the \(y\) equal to \(0\) and solve for \(x\) to find the x-intercept:\[2x-\sqrt{x}^2+1=0\]simplify the radical:\[2x-x+1=0\]combine like terms:\[x+1=0\]subtract 1 to isolate \(x\):\[x=-1\]^so that's the x-intercept

now to find the y-intercept, set all the \(x\)'s equal to \(0\):\[2(0)-\sqrt{0}^2+1=y\]simplify the radical:\[2(0)-0+1=y\]multiply:\[0-0+1=y\]combine like terms:\[1=y\]
\[\text{the x and y intercepts are (-1,0) and (0,1), respectively.}\]
hope this helps! :) @Ephilo

Answer 3

@yummydum yes ! a lot !!

Answer 4

\[\huge\ddot\smile\]

Answer 5

@yummydum im stuck another one can you help me with it too? please

Answer 6

sure, post another question

Answer 7

i kind of get this one but i'm lost in the middle
Find the points of intersection of the graphs of the equations:
x²+y²=25
2x+y=10

Answer 8

@yummydum ^^

Answer 9

for this one you'll have to graph
graph them both and see where they intersect

Answer 10

okay thanks (: