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can someone explain to me how to solve this problem...
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Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).
to get the equation of a line, you'll need the slope of the line and a point that is on that line so you can write it in point-slope form.... since it has to be perpendicular to 3x+y=7, do you know how to get the slope that is perpendicular to this line?
i think u the slope is the reciprocal of the slope in the equation,,right?
@dpaInc
well, it's the negative reciprocal....
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so what is the slope of the line with equation 3x+y=7 ????
-1/3?
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