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A 10m uniform beam, weighing 110N, is supported by two ropes at the ends, If a 380N person sits at 2.5m from the left end of the beam, what is the tension in each rope.
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Are you familiar with moments?
No, just torque
hmm, using torque to solve this will be slightly complex. Didn't you learn moments before learning about torque?
No, this is Physics I and we were never taught moments
I am not even sure if you'd use torque to solve for this problem
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okay... since the beam is not moving, Total torque =0. \(\Sigma \tau = \Sigma Fd\) |dw:1354412041449:dw| in this case, as the beam is uniform, the center of weight is in the center. taking the torque at \(T_1\) \(2.5(380)+5(110)=10(T_2)\) you follow?
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