Question

a)write the expression 32 ^-3/5 in radical notation.
b)Evaluate the radical expression.

Answer 1

\('5' \implies \sqrt[5]{Something}\)
\("-3" \implies \dfrac{1}{Something^{3}}\)

Answer 2

I think its this: \[\frac{ 1 }{ \sqrt[5]{32^{3}} }\]
Not entirely sure

Answer 3

how do I evaluate the expression ?

Answer 4

take the fifth root of 32 first
the fifth root of 32 is 2, because \(2^5=32\)

Answer 5

It is easier this way: \(\dfrac{1}{\left(\sqrt[5]{32}\right)^{3}}\)

Answer 6

then take 2 and cube it. \(2^3=2\times 2\times 2=8\)