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i have a quick x intercept question
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so the equasion is\[f(x)= x ^{4}-4x ^{3}\] i have to find what values of x make it = 0 in this form, the answer is x=0 but! if i change it to \[f(x)=x ^{3}(x-4)\] then the answer is x=0, x=4 which one is right?
you are missing something
if you factorize it then it become f(x) = x^2 (x^2 - 4 )
now x=0 and x=2 ----> this is the right answer
it's a quartic function, so i can have up to 4 roots (x ints) so both are intercepts are acceptable given that the values are within the domain of the function, or within an interval that is, otherwise, specified.
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ps the person underneath you didn't factor correctly
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