Question

please help!!
how do u solve for b^3+20b=9b^2?

Answer 1

rewrite the equation so that you have

\[b^3 - 9b^2 + 20b = 0\]

now take b as a common factor

\[b(b^2 - 9b + 20) = 0\]

factor the quadratic in the brackets... you need the factors of 20 than add to -9.... they are both negatives...

then you should be able to find the solutions.

Answer 2

so is it 5 and 4?

Answer 3

well you'll have

\[b(b -5)(b-4) = 0\]

so the solutions are b = 0, 4, 5

Answer 4

thank you