Find all the zeroes of the equation. –3x4+ 27x2 + 1200 = 0
-3(x^4 - 9x^2 - 400) = 0
So it is because the GCF is -3??
yea....
I know the real roots are -5 and 5. Don't I need that to find out??
so they already gave you these roots? u shouldve put put them along with the question
use synthetic division then!
use that synthetic division to find the other roots
No, I figured out the roots with a graphing calculator and my answers were off after doing synthetic division.
ok!!
Alright. I'll just re-do the problem and thanks for the help( :
om wait! lets work it out tpgether!
Alright.
do you know how to find rational zeros?
So I need to figure out the zeros of the equation –3x4+ 27x2 + 1200 = 0. In my book it tells me that I need to find the real roots which are -5 and 5 and then use the synthetic division.
I'm sure I would if I saw how to but not really.
oh ok! -3(x^4 - 9x^2 - 400) = 0 -3(x^2 - 25)(x^2 + 16) = 0
Set each factor equal to zero
x^2 - 25 = 0 x = 5, -5
Ohh! This is where I get confused...what do I need to do with -3?
x^2 + 16 = 0 x = 4i, -4i
Just leave that out!!!
Because when you set =3 equal to zero: -3 = 0 they are NOT equal to zero!!!!!
But when you simplify, you should write it out as: -3(x^2 + 16)(x-5)(x+5) = 0
Nope! They aren't equal to 0. And I get it now!! Thanks for your help( :
Its ok!! Thank you for the medal!!!!!!! :)
No problem( :
:)
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