Solve: 3n^2-8n+5
Was there an equation of some sort? Did you try factoring?
no didn't factor yet, i don't know how to solve this question at all.
It should say "=0" or something. Does it?
no it doesn't just says factor each polynomial
I see. The "solve" is just not the right word. "Factor" would be correct. 3n^2 -8n + 5 There is only one factorization of '3', so the factored result MUST look like this: (3n _____)(n _____) "5" is positive, so the factored result MUST look like one of these: (3n - _____)(n - _____) or (3n + _____)(n + _____) What do you suppose we should do next?
3n-1???
What factorizations of 5 are there? 1*5. That's it. Since ther is only one factorization of 5, the answer must be one of these: (3n - 1)(n - 5) or (3n + 1)(n + 5) or (3n - 5)(n - 1) or (3n + 5)(n + 1) Wihtout multiplying all of those, how can we use the -8 to throw out two of them?
that's the problem that i am having i am confused.
No need to be confused. Just get the rules stuck in your head. If you had to multipy those four things, could you do it? Show me one. (3n + 1)(n + 5) = ??
Is this the solution? (3n-5) (n-1)
Why would you ask that? Are you just guessing? Did you follow some process?
yes is is the solution because when you end up with 3n^2-3n-5n+5= 3n^2-8n+5
How did you decide that was a possibility?
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