Question

The perimeter of an equilateral triangle is 11 inches more than the perimeter of a square, and the side of the triangle is 6 inches longer than the side of the square. Find the side of the triangle

Answer 1

u can put that to two equations as
(a = side of triangle, b = side square)
3a =4b+11
a=b+6

Answer 2

Pathagorean Theorem: \[A^{2}+B^[2]=C^[2]\]

Answer 3

got it?

Answer 4

not yet i'm having trouble with it

Answer 5

(a = side of triangle, b = side square).
3a is the perimeter of triangle, 4b perimeter of square.
from question , a perimeter relationship can be found as
3a =4b+11 (perimeter of triangle = perimeter of square+ 11)

Answer 6

similarly the side relationship can be found out as
a= b+6
nw u hav 2 equations , can't u solve it.........