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and another one......plz help
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\[\frac{ 2a+3 }{ 4a-5 }-\frac{ a-2 }{ 4a-5}\]
How would you do this? \(\dfrac{7}{3} - \dfrac{13}{5}\)?
Let me sse
i would cross multiply
Well, I hope you mean that you would find a commn denominator and then add. Very good. Can you do that with the original problem statement?
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same denominators... simply subtract numerators
ummmm.....idk
4a-5
(2a+3)-(a-2) ======== 4a-5
2a -a + 3 +2 = a+5 ---->numerator
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a+5 === --------> the answer 4a-5
ok i get it
:)
Great.
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