Question

find the equation of the tangent line to the graph of the given function at the given value x posted below

Answer 1

\[x^3\sqrt{x^3+8};x=1\]

Answer 2

find the derivative because derivative= slope then plug in your x value to get m or slope.

Answer 3

alright thanks man

Answer 4

3x^2 squared would just be 3x so you get 3x^(2)*3x. You know how to use the power rule right?

Answer 5

yeah i know power rule, quotient rule, ect...

Answer 6

why need power rule if you need to find the derivative and plug it in.

Answer 7

ok cool so using the power rule you get (3x^2)(3x) after plugging in x=1 you just get 9 so slope= 9 now you just need to find the y intercept y=mx+b

Answer 8

to do that you plug x=1 into original function, in order to find y.

Answer 9

then finally you plug in your y value, x value, and slope to calculate b or y intercept

Answer 10

let me know if you get stuck bro @CalcDerp102

Answer 11

so i know how to do this, but im confused where power rule comes into place i did the derivative and i get 27 + 1/2 but i know its not that

Answer 12

wait nvm i got it, thanks man! its y = 19/2x-13/2