Simplify. (4x^2-3xy-5y^2)-(2x^2+xy-3y^2)
\[(4x ^{2}-3xy-5y ^{2})-(2x ^{2}+xy-3y ^{2)}\]
.removing the parenthesis of th given eq. (4x^2-3xy-5y^2)-(2x^2+xy-3y^2) gives, = 4x^2-3xy-5y^2 - 2x^2 - xy + 3y^2 now try to simplify by adding and subtracting =?
@Eric668668? can you do it ?
It comes out to be \[2x ^{2}-4xy-8y ^{2}\]
add or subtract liked terms on = 4x^2-3xy-5y^2 - 2x^2 - xy + 3y^2 or this is the same as = 4x^2 - 2x^2 - 3xy - xy - 5y^2 +3y^2 =?
wolfram it!
you almost got it except in this one - 5y^2 +3y^2
(-5y^2)-(-3y^2)= - 5y^2 +3y^2
Okay, this is what I got: \[2x ^{4}-2xy-8y ^{4}\]
Is this correct?
on the first solution you got you almost got it except in this one - 5y^2 +3y^2=?
it shouldnt be in the 4th power
So the answer to - 5y^2 +3y^2=? is -16y^2
hhmm its just -5+3 = +3-5 =__? its not 8 or 16
So it's -2^2
yeahhh you are correct its -2 y^2 .... :D
So the full answer is 2x2−4xy−2y2
yup you are correct ... :D
Ohhh YAY!!! Thank You Soooooo Much!!!!!!!!!!!!!!!!!!!!!!!!!! :D
ok good luck njow ....enjoy solving :D
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