Question

which of the following is equivalent to.... 1-cos^2 ϴ/cos^2 ϴ? a.sec^2ϴ b.(csc^2ϴ)-1 c.tan^2 ϴ d.sin^2ϴ answer is C. but how?

Answer 1

is it
(1-cos^2x)/cos^2x or without brackets?

Answer 2

if its with brackets
(1-cos^2x)/cos^2x
now (1-cos^2x) = sin^2x so the above
= sin^2x / cos^2x = tan^2x

C

Answer 3

its without brackets.... i know the answer but i would like to know how??

Answer 4

without brackets doesn't make sense\[1-\cos ^2\theta/\cos ^2\theta=1-1=0\]

Answer 5

\[1-\cos^2\theta/\cos^2\theta \]

Answer 6

that's exactly how it is on the paper without brackets..

Answer 7

well the guys who wrote the paper must have forgotten the brackets

Answer 8

Jithinkv is correct