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OpenStudy (anonymous):
\[\tan \sqrt{3}/3\]
OpenStudy (anonymous):
sorry, tan (theta) sqrt3/3
OpenStudy (anonymous):
tan theta = sqrt 3 /3 ?
OpenStudy (anonymous):
yeah, there are aparently 6 solutions
OpenStudy (anonymous):
like a formula solution
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OpenStudy (anonymous):
how to you find theta you mean? use arctan aka tan^-1
OpenStudy (anonymous):
well 5pi/6 is one of the solutions
so how would i write a formula solution?
OpenStudy (anonymous):
sqrt3/3 = sqrt3/(sqrt3)^2 = 1/sqrt3
tan theta=1/sqrt3
so the answer is 30
OpenStudy (anonymous):
pi/6
OpenStudy (anonymous):
(1/6)*Pi and there ar an infinite amnt of solotions. Cuzz it is a trig function.
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OpenStudy (anonymous):
other wise just use calc in radian mode to get
tan(3√/3)=0.6513878868
OpenStudy (anonymous):
well thats not what im looking for, thank you. the answer on the back of my book says theta=5pi/6+kpi and i dont know how they got that answer
OpenStudy (anonymous):
the + kpi just means that every k_pi it repeats.
OpenStudy (anonymous):
how do you get 5pi/6?
OpenStudy (anonymous):
well when I and edwardp did it we used calculators to find arctan and it gave us
(1/6)*Pi which is pi/6
Put since it is repeating. I assume that 5pi/6 is also an answer.
Just my guess.
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