10-16x-x=0 please help! i need to find
vertex and asymptote

Question

10-16x-x=0 please help! i need to find 
vertex and asymptote

lasttccasey · Answer

This is a straight line? Cleans up to be$$y=-17x+10$$

anonymous · Answer

no like your supposed to get two different x's and then plug them in or something so that you can get the asymptote and the vertex

lasttccasey · Answer

Straight lines don't have vertexes or asymptotes. Make sure you wrote the equation correctly. There should at least be an x^2 somewhere.

anonymous · Answer

oh yeah oops its 10-16x-x^2=0

anonymous · Answer

hello?

anonymous · Answer

well i have to go maybe you can help me later so bye ^-^

lasttccasey · Answer

Okay cleaning this up into the ax^2+bx+c=0 format we can quickly find the vertex:
-x^2-16x+10
Vertex = (h,k)

h=-b/2a
h=-(-16)/(2*(-1))
h=-8

Plus h back into the equation for the x values to find the k value:
-(-8)^2-16(-8)+10=k
k=74

Thus the vertex is (-8,74)

lasttccasey · Answer

And there are no asymptotes for parabolas.