Question

sin^2(x-1)/cos(-x)

Answer 1

@amistre64

Answer 2

might need to know alittle more about the question

Answer 3

It just says to simplify @amistre64

Answer 4

already seems "simple" to me :/

Answer 5

you can try to shuffle some things about i spose; sin^2 = 1-cos^2

cos(a+b) = cosa cosb - sina sinb and stuff

Answer 6

cos(-x) = cos(x) ... just some basic trig identities and properties that might be useful

Answer 7

@amistre64 would you like the possible answers?

Answer 8

Also quick question on another problem I'm stuck on.

Answer 9

options would be able to narrow it down :)

Answer 10

@amistre64 You there?

Answer 11

@saifoo.khan

Answer 12

A. -sinx
B. cosx
C. Sinx
D. -cosx

Answer 13

Where are you stuck? @Lukecrayonz

Answer 14

@saifoo.khan don't even know where to start :'(((

Answer 15

Use the 4th identity for numerator.
http://www.a-levelmathstutor.com/images/trigonometry/ca-identities01.jpg

Answer 16

The one Sin(A-B)?

Answer 17

Yep.

Answer 18

How.. That makes no sense to me?

Answer 19

If its sin^2 how would I use Sin(A-B)?

Answer 20

Ohhh. :o

Answer 21

hmm?

Answer 22

I think I got it

Answer 23

I guess, @satellite73 or @amistre64 will help you here. :/

Answer 24

sin^2x-1=-cos^2x
cos(-x)=cosx
so the answer is -cosx

Answer 25

Wait. How?

Answer 26

-cos^2x/cosx=-cosx?

Answer 27

Step 1.

Answer 28

cos(-x)=cosx

Answer 29

Pythagorean identities sin^2x+cos^2x=1

Answer 30

\[\frac{-\cos^2(x-1) +1}{\cos(-x)}\]Then we should get this?

Answer 31

shuffling trigs is a pain :)

Answer 32

No pain, no gain. ;)

Answer 33

do you need to show work?

Answer 34

http://www.wolframalpha.com/input/?i=simplify+sin%5E2%28x-1%29%2Fcos%28-x%29+

i dont see it popping out an option that you have