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Someone knows how to integrate sqrt(1+x³)dt?
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Since you're integrating with respect to dt, you can pull sqrt(1+x^3) outside the integral and the integral is just: \[\sqrt{(1+x^3)} \int\limits_{}^{}dt=t \sqrt{(1+x^3)}+C\]
@Kainui : I think he meant dx. Could be a typo.
In that case, good luck. http://www.wolframalpha.com/input/?i=sqrt%281%2Bx%C2%B3%29dx
Fun stuff bro! >.< .
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