Question

√3-i in polar form?

Answer 1

here
x=\[\sqrt{3}\]
y=-1
\[r=\sqrt{x^2+y^2}\]
\[\alpha=\tan^{-1} (y/x)\]
alpha will be negative, since it is in 4th quadrant

polar form will be r(cosx +isnx) {x=alpha}
2(cos30-isin30)