Help? How would I solve this? Identify the x and y intercepts for the equation 4x – 3y = 12. (4, 0) and (0, -3) (3, 0) and (0, -4) (4, 0) and (0, 3) (-3, 0) and (0, 4) (3, 0) and (0, 4)
would the first one be the answer?
2nd one
why is that?
see u can find it by reducing the equation to intercept form that is (x/a) +(y/b)=1 and the reqd intercept will be (a,0) and (0,b)
to get x intercept put y=0 in the eqn , u will get x=3 the x inercept is (3,0) now put x=0 to get y intercpt, y=-4 y intercept is (0,-4)
here u r given 4x-3y=12 or (4x-3y)/12=1 or 4x/12 -3y/12 =1 or x/3 -y/4=1 or x/3 +(y/(-4))=1 thus the points where the given line meets x and y axis respectively are (3,0) and (0,-4)
thus second option of ur answer is correct
oh okay, thank you guys!!
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