Question

the difference of two numbers is 1 and the sum of their squares is 41, find the numbers

Answer 1

You have to translate the words into math symbols.

Answer 2

ok i know that x-x=1

Answer 3

and the exponents have to give me 41

Answer 4

For your first response, it would be better if you use a different variable for each number rather than x and x.

Answer 5

x-y=1

Answer 6

You are pretty good at this. You need to do the same thing for the second part.

Answer 7

ok but

Answer 8

Yah

Answer 9

what would the answer be

Answer 10

if your variables are x and y, how do you write the sum of their square ?

Answer 11

aaahh i dont know

Answer 12

(5,4)?

Answer 13

if the variable is x, the square of that variable is \[x^{2}\]

likewise with the other variable ...and the sum of both is ? ...try to write that expression

Answer 14

x^2-y^2=1

Answer 15

2+2?

Answer 16

no no

Answer 17

the sum, not the difference ...and the sum of them is 41..do that again ?

Answer 18

4 and 5

Answer 19

where do you get 4 and 5 ?

Answer 20

five minus four is 1 and 4^2+5^2 is 41

Answer 21

that's guessing, you guess right, but it's not the way to solve :)

you have to write a system of 2 equations and try to solve it.